Two resistance wires on joining in parallel the resultant resistance is $\frac{6}{5}\,ohms$. One of the wire breaks, the effective resistance is $2\,ohms$. The resistance of the broken wire is ............ $ohm$
Medium
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Suppose resistance of wires are ${R_1}$ and ${R_2}$ then $\frac{6}{5} = \frac{{{R_1}{R_2}}}{{{R_1} + {R_2}}}$. If ${R_2}$ breaks then ${R_1} = 2\,\Omega $
Hence, $\frac{6}{5} = \frac{{2 \times {R_2}}}{{2 + {R_2}}} \Rightarrow {R_2} = 3\,\Omega $.
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