Question
Two resistors having resistance 4𝛀 and 6𝛀 are connected in parallel. Find their equivalent resistance.
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Answer

Let ' $R$ be their equivalent resistance of the $4 \Omega$ and $6 \Omega$ resistors connected in parallel
Then, $\frac{1}{R}=\frac{1}{4}+\frac{1}{6}=\frac{3+2}{12}=\frac{5}{12} \Omega$
Or, $R=\frac{12}{5}=2.4 \Omega$
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