Two resistors of $6\,\Omega $ and $9\,\Omega $ are connected in series to a $120\, volt$ source. The power consumed by the $6\,\Omega $ resistor is ........... $W$
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(a) Current through the combination $i = \frac{{120}}{{(6 + 9)}} = 8\,A$
So, power consumed by $6\,\Omega$ resistance
$P = {(8)^2} \times 6 = 384\,\,W$
So, power consumed by $6\,\Omega$ resistance
$P = {(8)^2} \times 6 = 384\,\,W$
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