$x_{1}=5 \sin \left(2 \pi t+\frac{\pi}{4}\right)$
$x_{2}=5 \sqrt{2}(\sin \pi t+\cos 2 \pi t)$
The amplitude are,
$A_{1}=5$
$A_{2}=\sqrt{(5 \sqrt{2})^{2}+(5 \sqrt{2})^{2}}=10$
The ratio of the amplitude is,
$\frac{A_{1}}{A_{2}}=\frac{5}{10}=1: 2$




If the position and velocity of the particle at $t=0\, {s}$ are $2\, {cm}$ and $2\, \omega \,{cm} \,{s}^{-1}$ respectively, then its amplitude is $x \sqrt{2} \,{cm}$ where the value of $x$ is ..... .