MCQ
Two stones having different masses $m_1$ and $m_2$ are projected at an angle $\alpha$ and $\left(90^{\circ}-\alpha\right)$ with same speed from same point. The ratio of their maximum heights is
  • A
    $1: 1$
  • B
    $1: \tan \alpha$
  • C
    $\tan \alpha: 1$
  • $\tan ^2 \alpha: 1$

Answer

Correct option: D.
$\tan ^2 \alpha: 1$
d
(d)

$H \propto \sin \alpha$

$\therefore \quad \frac{H_1}{H_2}=\frac{\sin ^2 \alpha}{\sin ^2\left(90^{\circ}-\alpha\right)}=\tan ^2 \alpha$

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