MCQ
Two waves of intensity $ I $ undergo Interference. The maximum intensity obtained is
- A$I / 2$
- B$I$
- C$2I$
- ✓$4I$
✓
Answer
Correct option: D.
$4I$
d
(d)For maximum intensity $\phi = 0^\circ $
$I = {I_1} + {I_2} + 2\sqrt {{I_1}{I_2}} \cos \phi $$ = I + I + 2\sqrt {I\,I} \cos 0^\circ = 4I$
(d)For maximum intensity $\phi = 0^\circ $
$I = {I_1} + {I_2} + 2\sqrt {{I_1}{I_2}} \cos \phi $$ = I + I + 2\sqrt {I\,I} \cos 0^\circ = 4I$
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