$R _{ net }=\frac{ R _{1} R _{2}}{ R _{1}+ R _{2}}$
$\frac{\rho \ell}{2 A }=\frac{\rho_{1} \frac{\ell}{ A } \times \rho_{2} \frac{\ell}{ A }}{\rho_{1} \frac{\ell}{ A }+\rho_{2} \frac{\ell}{ A }}$
$\frac{\rho}{2}=\frac{6 \times 3}{6+3}=2$
$\rho=4$


Reason : Resistance of wire is proportional ot resistivity of material.