MCQ
$\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{A} \xrightarrow{{4\,KO{H_1}{O_2}}}\mathop {2\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{B} }\limits_{(Green)}  + 2{H_2}O$

$3\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{B} \xrightarrow{{4\,HCl}}\mathop {2C}\limits_{(Purple)}  + Mn{O_2} + 2{H_2}O$

$3\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} \xrightarrow{{{H_2}O,KI}}2\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{A}  + 2KOH + \underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{D} $

In the above sequence of reactions, $\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{A}$ and $\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{D} $ ,  respectively are

  • A
    $KI$ and $KMnO_4$
  • $MnO_2$ and $KIO_3$
  • C
    $KIO_3$ and $MnO_2$
  • D
    $KI$ and $K_2MnO_4$

Answer

Correct option: B.
$MnO_2$ and $KIO_3$
b
$Mn{O_2}\,\xrightarrow{{4KOH,\,{O_2}}}\mathop {2{K_2}Mn{O_4}}\limits_{(Green)} \, + \,2{H_2}O$

$3{K_2}Mn{O_4}\,\xrightarrow{{4\,HCl}}\mathop {2KMn{O_4}}\limits_{(purple)} \, + \,Mn{O_2}\, + \,2{H_2}O$

$2KMn{O_4}\,\xrightarrow{{{H_2}O,\,KI}}2Mn{O_2}\, + \,2KOH\, + \,KI{O_3}$

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