Question
Using factor theorem, show that g(x) is a factor of p(x), when
p(x) = x3 - 8, g(x) = x - 2

Answer

f(x) = (x3 - 8)
By the Factor Theorem, (x - 2) will be a factor of f(x) if f(2) = 0.
Here, f(2) = (2)3 - 8
= 8 - 8 = 0
$\therefore$ (x - 2) is a factor of (x3 - 8).

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