Gujarat BoardEnglish MediumSTD 9MathsPolynomials2 Marks
Question
Using factor theorem, show that g(x) is a factor of p(x), when p(x) = x3 - 8, g(x) = x - 2
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Answer
f(x) = (x3 - 8) By the Factor Theorem, (x - 2) will be a factor of f(x) if f(2) = 0. Here, f(2) = (2)3 - 8 = 8 - 8 = 0 $\therefore$ (x - 2) is a factor of (x3 - 8).
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