Question
Using the formula for squaring a binomial, evaluate the following: $(1001)^2$
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Answer
Here, we will use the identity $(a + b)^2= a^2+ 2ab + b^2$.
$ (1001)^2 $
$ =(1000+1)^2 $
$ =(1000)^2+2 \times 1000 \times 1+1^2 $
$ =1000000+2000+1 $
$ =1002001 $
$ (1001)^2 $
$ =(1000+1)^2 $
$ =(1000)^2+2 \times 1000 \times 1+1^2 $
$ =1000000+2000+1 $
$ =1002001 $
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