Question
Verify that: $\frac{-1}{2}$ is a zero of the polynomial, $g(y) = 2y + 1.$

Answer

$\text{p}(\text{y}) = 2\text{y}+ 1$ $\Rightarrow\text{p}\Big(-\frac{1}{2}\Big)=2\times\Big(-\frac{1}{2}\Big)+1$ $=-1+1$ $=0$ Hence, $-\frac{1}{2}$ is the zero of the given polynomial.

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