Question
Verify the Rolle’s theorem for each of the functions:
$\text{f(x)}=\sqrt{4-\text{x}^2}\text{ in }[-2,2].$
$\text{f(x)}=\sqrt{4-\text{x}^2}\text{ in }[-2,2].$
[since every polynomial function is a continuous function]
Hence, f(x) is continuous in [-2, 2]
$=-\text{x}\cdot\frac{1}{\sqrt{4-\text{x}^2}},$ which exists everywhere except at $\text{x}=\pm2.$
Hence, f(x) is differentiable in (-2, 2).
$\Rightarrow\ \text{f}(-2)=\text{f}(2)$
Conditions of Rolle’s theorem are satisfied.
Hence, there exists a real number c such that f'(c) = 0
$\Rightarrow\ -\text{c}\frac{1}{\sqrt{4-\text{c}^2}}=0$
$\Rightarrow\ \text{c}=0\in(-2,2)$
Hence, Rolle’s theorem has been verified.
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