Question
Very-Short-Answer Question:
Write the zeros of the polynomial $x^2- x - 6$
Write the zeros of the polynomial $x^2- x - 6$
✓
Answer
We have,
$ f(x)=x^2-x-6 $
$ =x^2-3 x+2 x-6 $
$= x(x - 3) + 2(x - 3)$
$= (x + 2)(x - 3)$
$\therefore f(x) = 0$
$\Rightarrow (x + 2)(x - 3) = 0$
$\Rightarrow x + 2 = 0 or x - 3 = 0$
$\Rightarrow x = -2$ or $x = 3$
So, the zeros of $f(x)$ are $-2$ and $3$.
$ f(x)=x^2-x-6 $
$ =x^2-3 x+2 x-6 $
$= x(x - 3) + 2(x - 3)$
$= (x + 2)(x - 3)$
$\therefore f(x) = 0$
$\Rightarrow (x + 2)(x - 3) = 0$
$\Rightarrow x + 2 = 0 or x - 3 = 0$
$\Rightarrow x = -2$ or $x = 3$
So, the zeros of $f(x)$ are $-2$ and $3$.
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