We have a galvanometer of resistance $25\,\Omega $. It is shunted by a $2.5\,\Omega $ wire. The part of total current that flows through the galvanometer is given as
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(a) $\frac{i}{{{i_g}}} = \frac{{G + S}}{S}$
$ \Rightarrow $ $\frac{{{i_g}}}{i} = \frac{S}{{G + S}} = \frac{{2.5}}{{27.5}} = \frac{1}{{11}}$
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