- A$N{O_2}$ will be evolved
- BA white ppt. of $AgCl$ will be formed
- C$CC{l_4}$ will dissolve in $AgN{O_3}$
- ✓Nothing will happen
$CC{l_4}$ is a covalent compound. Therefore does not provide $C{l^ - }$ ions.
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A graph is plotted between concentration and time as shown. Effect$-1$ & Effect$-2$ are due to respectively

Statement $I:$ The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statement $II:$ The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of $H$-bonding.
In the light of the above statements, choose the most appropriate answer from the options given below :