MCQ
What is $\mathrm{A}$ in the following reaction?


- A

- ✓

- C

- D








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$CH_3CH(Cl)CH_2 - CH_2OH \xrightarrow{Aq.KOH}$ is
| List-$I$ (Compound) | List-$II$ (Colour) |
| $A$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH}_2 \mathrm{O}$ | $I$ Violet |
| $B$ $\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$ | $II$ Blood Red |
| $C$ $[\mathrm{Fe}(\mathrm{SCN})]^{2+}$ | $III$ Prussian Blue |
| $D$ $\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3$ | $IV$ Yellow |
Choose the correct answer from the options given below :
The decreasing order of the rate of the above reaction with nucleophiles $(Nu^-)$ $A$ to $D$ is
$[Nu^-=(A) \,PhO^-, (B)\,AcO^-, (C)\, HO^-, (D)\, CH_3O^-]$