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| List-$I$ | List-$II$ |
| $\mathrm{P}_2 \mathrm{O}_3+3 \mathrm{H}_2 \mathrm{O} \rightarrow$ | $\mathrm{P}(\mathrm{O})\left(\mathrm{OCH}_3\right) \mathrm{Cl}_2$ |
| $\mathrm{P}_4+3 \mathrm{NaOH}+3 \mathrm{H}_2 \mathrm{O} \rightarrow$ | $\mathrm{H}_3 \mathrm{PO}_3$ |
| $\mathrm{PCl}_5+\mathrm{CH}_3 \mathrm{COOH} \rightarrow$ | $\mathrm{PH}_3$ |
| $\mathrm{H}_3 \mathrm{PO}_2+2 \mathrm{H}_2 \mathrm{O}+4 \mathrm{AgNO}_3 \rightarrow$ | $\mathrm{H}_3 \mathrm{PO}_4$ |
$[X]$ $\xrightarrow{{KMn{O_4}/\mathop O\limits^\Theta H/\Delta }}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{HOOC - {{(C{H_2})}_3} - CH - COOH}
\end{array}}
\end{array}}
\end{array}$
$[X]$ will be: