- A$O_2^ + > O_2^ - > {O_2}$
- ✓$O_2^ + > {O_2} > O_2^ - $
- C${O_2} > O_2^ - > O_2^ + $
- D$O_2^ - > O_2^ + > {O_2}$
$B.O$ $-2.5$ $2$ $1.5$
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Assertion $(A):$ The ionic radii of $O ^{2-}$ and $Mg ^{2+}$ are same.
Reason $( R )$ : Both $O ^{2-}$ and $Mg ^{2+}$ are isoelectronic species.
In the light of the above statements, choose the correct answer from the options given below


Product in above reaction is
$\begin{array}{|l|l|} \hline \,\,List\,\,\,\,I\,\,(Compound) & \,\,List\,\,II\,\,(Oxidation\,\,state\,\,of\,\,N) \\ \hline (A)\,\,N{{O}_{2}} & (1)\,\,\,\,+\,\,5 \\ \hline (B)\,\,HNO & (2)\,\,-\,\,3 \\ \hline (C)\,\,N{{H}_{3}} & (3)\,\,+\,\,4 \\ \hline (D)\,\,{{N}_{2}}{{O}_{5}} & (4)\,\,+\,\,1 \\ \hline \end{array}$
code : $A \,\, B \,\,C \,\,D$