MCQ
What is integrating factor of $\frac{\text{dy}}{\text{dx}}+\text{y}\sec\text{x}=\tan\text{x}?$
  • $\sec\text{x}+\tan\text{x}$
  • B
    $\log(\sec\text{x}+\tan\text{x})$
  • C
    $\text{e}^{\sec\text{x}}$
  • D
    $\sec{\text{x}}$

Answer

Correct option: A.
$\sec\text{x}+\tan\text{x}$
We have,$\frac{\text{dy}}{\text{dx}}+\text{y}\sec\text{x}=\tan\text{x}$
Comparing with We get,
$\text{P}=\sec{\text{x}}, \text{Q}=\tan{\text{x}}$
Now,
$\text{I.F}=\text{e}^{\int\sec\text{x}\text{dx}}$
$=\text{e}^{\log(\sec\text{x}+\tan\text{x})}$
$=\sec\text{x}+\tan\text{x}$

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