Question
What is nucleophilic substitution reaction ? Write down different products obtained from alkyl halides.

Answer

$\rightarrow$ Nucleophiles are electron rich species.
Therefore, they attack at that part of the substrate molecule which is electron deficient.
$\rightarrow $ The reaction in which a nucleophile replaces already existing nucleophile in a molecule is called nucleophilic substitution reaction.
$\rightarrow$ Haloalkanes are substrate in these reactions.
Image
$\rightarrow$ In this type of reaction, a nucleophile reacts with haloalkane $($the substrate$)$ having a partial positive charge on the carbon atom bonded to halogen.
$\rightarrow$ A substitution reaction takes place and halogen atom, called leaving group departs as halide ion.
Since the substitution reaction is initiated by a nucleophile, it is called nucleophilic substitution reaction.
$\rightarrow$ It is one of the most useful classes of organic reactions of alkyl halides in which halogen is bonded to $SP^3$ hybridised carbon.
$\ce{R - X + Nu ^{-} \rightarrow R - Nu + X ^{-}}$​​​​​​​
Reagent Nucleophile
$(Nu^-)$
Substitution
product
$R-Nu$
Class of main
product
$NaOH (KOH)$ $HO^-$ $ROH$ Alcohol
$H₂O$ $H₂O$ $ROH$ Alcohol
$NaOR'$ $R'O^-$ $ROR'$ Ether
$Nal$ $Γ$ $R-I$ Alkyl iodide
$NH_3$ $NH_3$ $RNH_2$ Primary amine
$R'NH₂$ $R'NH_2$ $RNHR'$ Sec. amine
$R'R"NH$ $R'R"NH$ $RNR'R"$ Tert. amine
$KCN$ $\overline{ C } \equiv N :$ $RCN$ Nitrile $($cyanide$)$
$AgCN$ $Ag-CN$ $RNC$ Isonitrile $($isocyanide$)$
$KNO_2$ $O = N - O$ $R-O-N=O$ Alkyl nitrite
$AgNO_2$ $Ag -\ddot{ O }- N = O$ $R-NO_2$ Nitroalkane
$R'COOAg$ $R'COO^-$ $R'COOR$ Ester
$LiAlH _4$ $H$ $RH$ Hydrocarbon
$R'^-M^+$ $R'$ $RR'$ Alkane

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