MCQ

What is the distance between (1, 3) and (5, 6):

  • A
    3 units
  • B
    4 units
  • C
    5 units
  • D
    25 units

Answer

  1. 5 units

Solution:

We know, distance between two points (x1, y1) and (x2, y2) is $\sqrt{(\text{x}_{1}−\text{x}_{2})^2+(\text{y}_{1}−\text{y}_{2})^2.}$

So, distance between (1, 3) and (5, 6) is $\sqrt{{(1-5)}^2+{(3-6)}^2}$

= (4)+ (3)2 = 5 units

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