What is the distance between (1, 3) and (5, 6):
- A3 units
- B4 units
- C5 units
- D25 units
What is the distance between (1, 3) and (5, 6):
Solution:
We know, distance between two points (x1, y1) and (x2, y2) is $\sqrt{(\text{x}_{1}−\text{x}_{2})^2+(\text{y}_{1}−\text{y}_{2})^2.}$
So, distance between (1, 3) and (5, 6) is $\sqrt{{(1-5)}^2+{(3-6)}^2}$
= (4)2 + (3)2 = 5 units
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$\text{T}_{5}$
$\text{T}_{6}$
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$2$
$0$
$1$
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