MCQ
What is the distance of (5, 12) from origin?
- A6 units.
- B8 units.
- C10 units.
- D13 units.
Solution:
We know, distance between two points (x1, y1) and (x2, y2) is $\sqrt{({\text{x}}_{1}-{\text{x}}_{2})^{2}+({\text{y}}_{1}-{\text{y}}_{2})^{2}}$
So, distance between (5, 12) from origin (0, 0) is $\sqrt{({5-0})^{2}+({12-0})^{2}} = \sqrt{({5})^{2}+({12})^{2}} =13\text{ unit}.$
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The area of the triangle formed by the points (a, b + c), (b, c + a) and (c, a + b) is: