Question
What is the distribution of electrons in an oxygen atom:
The total number of electrons present in oxygen is $8.$
Therefore, for $O$ electron configuration will be $1s^22s^22p^4.$
The distribution of electrons in oxygen atom is given by:
First orbit or $K$ shell $= 2(2n^{2 }= 2 \times 1^{1 }= 2)$
Second orbit or $L$ shell $= 6(8 − 2 = 6)$
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