MCQ
What is the $pH$ of $Ba{(OH)_2}$ if normality is $10$
- A$4$
- ✓$10$
- C$7$
- D$9$
One molecule on dissociation furnishes $2O{H^ - }$ ions.
So, $[O{H^ - }] = 2 \times {10^{ - 4}}N$
$N = M \times 2$ ; $M = \frac{N}{2} = \frac{{2 \times {{10}^{ - 4}}}}{2} = {10^{ - 4}}$
$pOH = - \log [O{H^ - }] = - \log (1 \times {10^{ - 4}}) = - 4$
$pH + pOH = 14$; $pH = 14 - 4 = 10$.
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{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - CH - CH - C{H_2} - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - C{H_{3\,\,\,\,}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$C ( s )+\frac{1}{2} O _{2}( g ) \rightarrow CO ( g )+100 \;kJ$
When coal of purity $60 \%$ is allowed to burn in presence of insufficient oxygen, $60 \%$ of carbon is converted into $'CO'$ and the remaining is converted into $'CO _{2}$$'$.
The heat generated when $0.6 \;kg$ of coal is burnt is