MCQ
What is the stopping potential when the metal with work function $0.6 \mathrm{eV}$ is illuminated with the light of $2 \mathrm{eV}$
- A$2.6 \mathrm{~V}$
- B$3.6 \mathrm{~V}$
- C$0.8 \mathrm{~V}$
- ✓$1.4 \mathrm{~V}$
✓
Answer
Correct option: D.
$1.4 \mathrm{~V}$
$V_0=\frac{\left(E-W_0\right)}{e}=\frac{(2 e V-0.6 \mathrm{eV})}{e}=1.4 \mathrm{~V}$
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