- Asin x + tan x sec x
- Bcos x + tan x sec x
- Csin x + tan x
- Dsin x + tan x sec2x
Solution:
We follow product rule $\frac{\text{d}}{\text{dx}}(\text{f}.\text{g})=\text{g.}\frac{\text{d}}{\text{dx}}(\text{f})+(\text{f})\frac{\text{d}}{\text{dx}}(\text{f}.\text{g})$
Here, f = sin x and g = tan x
$\frac{\text{d}}{\text{dx}}$ (sin x tan x) = cos x tan x + sec2 x sinx
$\frac{\text{d}}{\text{dx}}$ (sin x tan x) = sin x + tan x sec x
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