Question
What rational number should be added to $-\frac{3}{16}$ to get $\frac{11}{24}$

Answer


Sum of two numbers $=\frac{11}{24}$
One number $=-\frac{3}{16}$
$\therefore$ The required number $=\frac{11}{24}-\left(\frac{-3}{16}\right) \Rightarrow \frac{11}{24}+\frac{3}{16}$
224,16
212,8
26,4
23,2
33,1
1

L.C.M. of 16 and $24=2 \times 2 \times 2 \times 2 \times 3=48$
$ \begin{aligned} & (\because \text { L.C.M. of } 24,16=48) \\ & =\frac{11 \times 2}{24 \times 2}-\frac{3 \times 3}{16 \times 3} \end{aligned} $
$ =\frac{22+9}{48}=\frac{31}{48} $

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