Question
What should be added to $-2$ to get $\frac{3}{8}$ ?
✓
Answer
Let the required number be $=x$
According to the question,
$-2+ x =\frac{3}{8}$
$ \Rightarrow x =\frac{3}{8}+2$
$ \Rightarrow x =\frac{3+16}{8}=\frac{19}{8}=2 \frac{3}{8}$
$\therefore$ The required number $=\frac{19}{8}=2 \frac{3}{8}$
According to the question,
$-2+ x =\frac{3}{8}$
$ \Rightarrow x =\frac{3}{8}+2$
$ \Rightarrow x =\frac{3+16}{8}=\frac{19}{8}=2 \frac{3}{8}$
$\therefore$ The required number $=\frac{19}{8}=2 \frac{3}{8}$
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