MCQ
What will be the equivalent weight of $Mg ( A =24)$ in $MgCl _2$ ?
- ✓12
- B24
- C6
- D18
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${N_2}(g)\, + 3{H_2}(g)\, \rightleftharpoons \,2N{H_3}(g)$
The equilibrium constant of the above reaction is $K_3$. If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume that $P_{NH_3}<\,< P_{total}$ at equilibrium)