MCQ
What will be the order of Ist ionisation energy
- ✓$Li > Na > K$
- B$K > Li > Na$
- C$Na > Li > K$
- D$Li > K > Na$
$ Li$ $Na$ $K$ $Rb$ $cs$
$eV $ $5.3$ $5.1$ $4.3$ $4.2$ $3.9$
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$(i)$ $C{H_3}C{H_2}C{H_2}C{H_3}$
$(ii)$ $C{H_3} - CH = CH - C{H_3}$
$(iii)$ $C{H_2} = CH - CH = C{H_2}$
$(iv)$ $H - C \equiv C - H$

$STATEMENT-2$: The higher oxidation states for the group $14$ elements are more stable for the heavier members of the group due to 'inert pair effect'.