MCQ
What will happen if $LiAl{H_4}$ is added to an ester
- ✓Two units of alcohol are obtained
- BOne unit of alcohol and one unit of acid is obtained
- CTwo units of acids are obtained
- DNone of these
✓
Answer
Correct option: A.
Two units of alcohol are obtained
a
(a) $R - \mathop {\mathop C\limits^{||} }\limits^O - R'\xrightarrow{{LiAl{H_4}}}\mathop {R - C{H_2}OH + R'OH}\limits_{{\text{Two}}\,{\text{units}}\,{\text{of}}\,{\text{alcohols}}} $
(a) $R - \mathop {\mathop C\limits^{||} }\limits^O - R'\xrightarrow{{LiAl{H_4}}}\mathop {R - C{H_2}OH + R'OH}\limits_{{\text{Two}}\,{\text{units}}\,{\text{of}}\,{\text{alcohols}}} $
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→$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{C{H_2} - OH\,\,} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{C = O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{\,\,CH - OH\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - OH\,\,\,\,}
\end{array}\xrightarrow{{HI{O_4}}}$ Product obtained is
→{\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{C{H_2} - OH\,\,} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{C = O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{\,\,CH - OH\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - OH\,\,\,\,}
\end{array}\xrightarrow{{HI{O_4}}}$ Product obtained is
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