Question
When $_{15​}P^{30}$ decays to become $_{14​}Si^{30},$ which particle is released?

Answer

The nuclear reaction$: _{15}​P^{30} \rightarrow _4Si^{30}+ _{+1}​e^0$
Thus a positron is emitted during the decay of $_{15}​P^{30} $ into $_{14}​Si^{30}.$

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