MCQ
When 2-bromobutane reacts with alcoholic $KOH$, the reaction is called
- AHalogenation
- BHydrogenation
- CChlorination
- ✓Dehydro-halogenation
✓
Answer
Correct option: D.
Dehydro-halogenation
d
(d) $C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,}\limits_{Br\,} } - C{H_2} - C{H_3} \xrightarrow{alc.KOH} \mathop {C{H_3}CH = CHC{H_3}}\limits_{{\rm{2 - butene}}} $
The reaction is dehydrohalogenation.
(d) $C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,}\limits_{Br\,} } - C{H_2} - C{H_3} \xrightarrow{alc.KOH} \mathop {C{H_3}CH = CHC{H_3}}\limits_{{\rm{2 - butene}}} $
The reaction is dehydrohalogenation.
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