MCQ
When $3d$ orbital is complete, the new electron will enter the
- ✓$4p$-orbital
- B$4f$-orbital
- C$4s$-orbital
- D$4d$-orbital
✓
Answer
Correct option: A.
$4p$-orbital
a
(a) According to the Aufbau’s principle the new electron will enter in those orbital which have least energy. So here $4p$- orbital has least energy then the others.
(a) According to the Aufbau’s principle the new electron will enter in those orbital which have least energy. So here $4p$- orbital has least energy then the others.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Below conversion can be brought about by ?
The number of isomeric tetraenes (NOT containing $s p$-hybridized carbon atoms) that can be formed from the following reaction sequence is. . . . . .
→The correct order of first ionization enthalpy values of the following elements is:
(A) O
(B) N
(C) Be
(D) F
(E) B
Choose the correct answer from the options given below :
(A) O
(B) N
(C) Be
(D) F
(E) B
Choose the correct answer from the options given below :
Consider the following molecules : $\mathrm{Br}_3 \mathrm{O}_8, \mathrm{~F}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{~S}_4 \mathrm{O}_6, \mathrm{H}_2 \mathrm{~S}_5 \mathrm{O}_6$, and $\mathrm{C}_3 \mathrm{O}_2$.
→Count the number of atoms existing in their zero oxidation state in each molecule. Their sum is . . . . .
Radius of the isoelectronic species
An aqueous solution of a solute $AB$ has $b.p$ of $101.08\,^{\circ}C (AB$ is $100\%$ ionised in boiling point of the solution $)$ and freezes at $-1.80\,^{\circ}C.$ Hence $,AB\, (K_b / K_f = 0.3)$
→To carry out above conversion, $(A)$ and $(B)$ respectively, are
→The equivalent weight of a metal is $4.5$ and the molecular weight of its chloride is $80$. The atomic weight of the metal is
→When $\alpha $-particles are sent through a thin metal foil, most of them go straight through the foil because (one or more are correct)
→Identify product $(P)$
→