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Current Electricity — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsCurrent Electricity1 Mark
MCQ
When a $12 \Omega$ resistor is connected with a moving coil galvanometer then its deflection reduces from 50 divisions to 10 divisions. The resistance of the galvanometer is
  • A
    $24 \Omega$
  • B
    $36 \Omega$
  • ✓
    $48 \Omega$
  • D
    $60 \Omega$
✓

Answer

Correct option: C.
$48 \Omega$
(c) $i_g=\frac{i S}{S+G} \Rightarrow 10=\frac{50 \times 12}{12+G} \Rightarrow 12+G=60 \Rightarrow G=48 \Omega$

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