MCQ
When a body is thrown with a velocity $u$ making an angle $\theta$ with the horizontal plane, the maximum distance covered by it in horizontal direction is
- A$\frac{u^2 \sin \theta}{g}$
- B$\frac{u^2 \sin 2 \theta}{2 g}$
- ✓$\frac{u^2 \sin 2 \theta}{g}$
- D$\frac{u^2 \cos 2 \theta}{g}$
