MCQ
When a tuning fork of frequency $341$ is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork is
  • A
    $334$
  • B
    $339$
  • C
    $343$
  • $347$

Answer

Correct option: D.
$347$
(d) $n_{-}=$Known frequency $=341 \mathrm{~Hz}, n_s=$ ?$x=6$bps,
which is decreasing (i.e. $x \downarrow$ ) after loading (from 6 to 1 bps)
Unknown tuning fork is loaded so $n \downarrow$
Hence $n-n \downarrow=x \downarrow$ Wrong  $n \downarrow-n=x \downarrow \quad \ldots \text { (ii) } $
$\Rightarrow n=n+x=341+6=347 \mathrm{~Hz} $ $\longrightarrow \text { Correct }$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions