MCQ
When aluminium phosphide is treated with dil. sulphuric acid
- A$S{O_2}$ is liberated
- ✓$P{H_3}$ is evolved
- C${H_2}S$ is evolved
- D${H_2}$ is evolved
$2 AlP +\text { dil. } 3 H _2 SO _4 \rightarrow Al _2\left( SO _4\right)_3+2 PH _3 \text {. }$
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Reason : Addition of $HBr$ on $2-$ butene follows Markovnikov rule.
$Fe^{3+} + e \to Fe^{2+} ;$ $E^o = 0.771\, volts$
$I_2 + 2e\to 2I^-;$ $E^o = 0.536\, volts$
$E^o$ cell for the cell reaction
$2Fe^{3+} + 2I^-\to 2Fe^{2+} + I_2$ is
