MCQ
When copper is heated with conc. $HNO_3$ it produces
- A$Cu(NO_3)_2, NO$ and $NO_2$
- B$Cu(NO_3)_2$ and $N_2O$
- ✓$Cu(NO_3)_2$ and $NO_2$
- D$Cu(NO_3)_2$ and $NO$
$\mathrm{Cu}+4 \mathrm{HNO}_{3} \longrightarrow \mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}+2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{NO}_{2}$
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Product $(A)$ in above reaction is
