MCQ
When electric current is passed through an ionic hydride in the molten state:
  • Hydrogen is liberated at the anode.
  • B
    Hydrogen is liberated at the cathode.
  • C
    No reaction takes place.
  • D
    Hydride ion migrates towards cathode.

Answer

Correct option: A.
Hydrogen is liberated at the anode.
Lonic hydrides in their molten state can conduct electricity and on electrolysis liberate dihydrogen gas at anode, which confirms the existence of $H^-$ ion.
$2\text{H}^-(\text{melt})\xrightarrow{\text{Anode}}\text{H}_2(\text{g})+2\text{e}^-$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The oxidation state of manganese in $\mathrm{K}_2 \mathrm{MnO}_4$​ is:
Which of the following statement is wrong
In the reaction, $4N{H_3}_{(g)} + 5{O_2}_{(g)} \to 4NO_{(g)} + 6{H_2}O_{(g)}$, When $1$ mole of ammonia and $1$ mole of ${O_2}$ are made to react to completion
Assertion : Cyclopentadienyl anion is much more stable than allyl anion.
 
Reason : Cyclopentadienyl anion is aromatic in character.
A substance containing an equal number of primary, secondary and tertiary carbon atoms is:
In the final answer of the expression $\frac{{(29.2 - 20.2)\,(1.79 \times {{10}^5})}}{{1.37}}$. The number of significant figures is
For the reaction in equilibrium ${N_2}{O_4}(g)\, \rightleftharpoons \,2N{O_2}(g)$ the equilibrium concentrations $N_2O_4$ and $NO_2$ are $4.8 \times 10^{-2}$ and $1.2 \times 10^{-2}\,mol/L,$ then $K_C$ is
At $320\,K,$ a gas $A_2$ is $20\%$  dissociated to $A(g).$ The standard free energy change at  $320\,K$  and $1\,atm$   in $J\,mo1^{-1}$  is approximately

$(R= 8.314\,\,JK^{-1}\,\,mol^{-1};\,\,ln\,2 = 0.693;\,\,ln\,3 = 1.098)$

$\mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{3}+\mathrm{Cl}_{3} \quad \mathrm{~K}_{\mathrm{c}}=1.844$

$3.0$ $moles$ of $\mathrm{PCl}_{5}$ is introduced in a $1\, \mathrm{~L}$ closed reaction vessel at $380\, \mathrm{~K}$. The number of moles of $\mathrm{PCl}_{5}$ at equilibrium is $.....\,\times 10^{-3}$. (Round off to the Nearest Integer)

The correct order of equatorial $FSF$ bond angle in the following compound.

$(I)\, SF_4$             $(II)\, OSF_4$              $(III)\, H_2CSF_4$