MCQ
When ethyl iodide is heated with silver nitrate, the product obtained is
- A${C_2}{H_5}Ag$
- B$Ag - O - N{O_2}$
- ✓${C_2}{H_5}O - N{O_2}$
- D${C_2}{H_5}I - N{O_2}$
✓
Answer
Correct option: C.
${C_2}{H_5}O - N{O_2}$
c
(c)${C_2}{H_5} - I + AgN{O_3} \to {C_2}{H_5}ON{O_2} + AgI$
(c)${C_2}{H_5} - I + AgN{O_3} \to {C_2}{H_5}ON{O_2} + AgI$
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