MCQ
When fluoride is heated with conc. ${H_2}S{O_4}$ and $Mn{O_2}$ the gas evolved is
- A${F_2}$
- B$SF$
- ✓$HF$
- DNone
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$E_{\frac{1}{2}Cl_2/Cl^- }^o = 1.36\,V\,,\,E_{C{r^{3 + }}/Cr}^o = - 0.74\,V$
$E_{C{r_2}O_7^{2 - }/C{r^{3 + }}}^o = 1.33\,V\,,\,E_{MnO_4^ - /M{n^{2 + }}}^o = 1.51\,V$
The correct order of reducing power of the species $(Cr, Cr^{3+}, Mn^{2+}$ and $Cl^-)$ will be
$C{H_3} - C \equiv CH\xrightarrow{{Excess\,\, HCl}}\left( A \right)\xrightarrow{{{H_2}O/O{H^\Theta }}}\left( x \right)$
Product $(P)$ will be
The product $'B'$ is?