MCQ
When formic acid reacts with $PC{l_5}$ it forms
- ✓Formyl chloride
- BAcetyl chloride
- CMethyl chloride
- DPropionyl chloride
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$[Figure]$ $\xrightarrow[{2.\,C{H_3}I\,(l.\,eq.)}]{{1.\,{K_2}C{O_3}}}$
${C_6}{H_5}CHO+X\mathop {\xrightarrow{{(i)\,Zn\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}}\limits_{(ii)\,HOH/N{H_4}Cl} \begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{{C_6}{H_5} - CH - C{H_2} - COO{C_2}{H_5}}
\end{array}$
$[X]$ will be: