MCQ
When ${I_2}$ is passed through $KCl$, $KF$ and $KBr$ solutions
- A$C{l_2}$ and $B{r_2}$ are evolved
- B$C{l_2}$ is evolved
- C$C{l_2},\;B{r_2}$ and ${F_2}$ are evolved
- ✓None of these
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${C_6}{H_5}N{O_2}\xrightarrow{{Sn / HCl}}X\xrightarrow{{{C_6}{H_5}COCl}}Y + HCl$
What is $Y$ ?


Assertion $(A)$ : $\mathrm{S}_{\mathrm{N}} 2$ reaction of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{Br}$ occurs more readily than the $\mathrm{S}_{\mathrm{N}} 2$ reaction of $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Br}$.
Reason $(R)$ : The partially bonded unhybridized p-orbital that develops in the trigonal bipyramidal transition state is stabilized by conjugation with the phenyl ring.
In the light of the above statements, choose the most appropriate answer from the options given below: