- A$C{l_2}$ and $B{r_2}$ are evolved
- B$C{l_2}$ is evolved
- C$C{l_2},\;B{r_2}$ and ${F_2}$ are evolved
- ✓None of these
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(ii) Silver metal does not react with $1 M$ zinc nitrate solution
(iii) Zinc metal dissolves in $1M$ copper sulphate solution and copper metal gets depositedHence the order of decreasing strength of the three metals as reducing agents will be
${\left[\mathrm{V}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, \quad\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}, \quad\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},}$
${\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}}$
[Given atomic numbers: $\mathrm{V}=23, \mathrm{Cr}=24, \mathrm{Fe}=26$,
$\mathrm{Ni}=28, \mathrm{Cu}=29]$