MCQ
When iodine reacts with $NaF,$ $NaBr$ and $NaCl$
- AIt gives mixture of ${F_2},$ $C{l_2}$ and $B{r_2}$
- BIt gives chlorine
- CIt gives bromine
- ✓None of these
Because $I_2$ is least electronegative among halogens.
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| List $I$ Complex | List $II$ Crystal Field splitting energy $\left(\Delta_0\right)$ |
| $A$ $\left[ Ti \left( H _2 O \right)_6\right]^{2+}$ | $I$ $-1.2$ |
| $B$ $\left[ V \left( H _2 O \right)_6\right]^{2+}$ | $II$ $-0.6$ |
| $C$ $\left[ Mn \left( H _2 O \right)_6\right]^{3+}$ | $III$ $0$ |
| $D$ $\left[ Fe \left( H _2 O \right)_6\right]^{3+}$ | $IV$ $-0.8$ |
$(I)$ Only $C$ react with $0.10\, M\, HCl$ to give $H_2(g)$
$(II)$ When $A$ is added to solution of the other metal ions, metallic $D$ is formed but not $B$ or $C$


