MCQ
When $p(x) = x^3-3 x^2+4 x+32$ is divided by $(x + 2),$ the remainder is:
- A$0$
- B$32$
- C$36$
- ✓$4$
✓
Answer
Correct option: D.
$4$
$p(x)=x^3-3 x^2+4 x+32$
$x+2=0 \Rightarrow x=-2$
By the renainder theorem, we know that when $p(x)$ is divided by
$(\mathrm{x}+2)$, the remainder is $\mathrm{p}(-2)$.
$\text { Now, } p(-2)=x^3-3 x^2+4 x+32$
$=(-2)^3-3(-2)^2+4(-2)+32$
$=-8-12-8+32$
$=4$
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