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Redox Reactions — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions1 Mark
MCQ
When $\mathrm{SO}_2$ is passed through an acidified solution of $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7,$ then chromium sulphate is formed. Change in oxidation state of $\text{Cr}$ is from.
  • ✓
    $+4$ to $+2$
  • B
    $+6$ to $+3$
  • C
    $+7$ to $+2$
  • D
    $+5$ to $+3$
✓

Answer

Correct option: A.
$+4$ to $+2$
In acidic medium $\text{Cr}$ is reduced from $+6$ to $+3$ as :
$\mathrm{Cr}_2 \mathrm{O}_7^{-2}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{+3}+7 \mathrm{H}_2 \mathrm{O}$
and $\mathrm{SO}_2$ is oxidised to $\mathrm{SO}_3$ as :
$\mathrm{SO}_2+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{SO}_3+2 \mathrm{H}^{+}+\mathrm{e}^{-}$

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