MCQ
When tin is treated with concentrated nitric acid
- AIt is converted into stannous nitrate
- BIt is converted into stannic nitrate
- ✓It is converted into metastannic acid
- DIt becomes passive
$Sn + 4HN{O_3} \to {H_2}Sn{O_3} + 4N{O_2} + {H_2}O$
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$S\left( s \right) + {O_2}\left( g \right) \rightleftharpoons S{O_2}\left( g \right);{K_1} = {10^{52}}$
$2S\left( s \right) + 3{O_2}\left( g \right) \rightleftharpoons 2S{O_3}\left( g \right);{K_2} = {10^{129}}$
The equilibrium constant for the reaction $2S{O_2}\left( g \right) + {O_2}\left( g \right) \rightleftharpoons 2S{O_3}\left( g \right)$ is
Figure $\xrightarrow[{(ii)\,\,NaB{D_4}}]{{(i)\,\,Hg{{(OAc)}_2}\,{H_2}O}}Q$
Figure $\xrightarrow[{(ii)\,\,{H_2}{O_2}\,/\,O{H^ - }}]{{(i)\,\,B{D_6}\,,\,THF}}R$
Products $P, Q$ and $R$ are