MCQ
When treated with ammoniacal cuprous chloride, which one among the following forms copper derivative
- A${C_2}{H_6}$
- B${C_2}{H_4}$
- ✓${C_2}{H_2}$
- D${C_6}{H_6}$
✓
Answer
Correct option: C.
${C_2}{H_2}$
c
(c) $2N{H_4}OH + C{u_2}C{l_2} \to 2CuOH + 2N{H_4}Cl$
(c) $2N{H_4}OH + C{u_2}C{l_2} \to 2CuOH + 2N{H_4}Cl$
$N{{H}_{4}}OH+CuOH\to \underset{\begin{smallmatrix}
\text{Diammine copper} \\
\text{ }\left( I \right)\text{ hydroxide}
\end{smallmatrix}}{\mathop{[Cu{{(N{{H}_{3}})}_{2}}]OH}}\,$
$2[Cu{{(N{{H}_{3}})}_{2}}]\,OH+HC\equiv CH\to $ $\mathop {Cu - C \equiv C - Cu}\limits_{{\text{copper acetylide Red ppt}}{\text{.}}} + 4N{H_3} + 2{H_2}O$
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